what are the missing entries in the following table?
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hello in this lecture we will solve question in which we have to find two missing frequencies in previous lecture I explained about one missing frequency here I will explain about two missing frequencies so let us start let us say this is my question so this is my question these two columns will be given in the question paper you have to make X I you know how to make X I sum of these 2 divided by 2 0 plus 4 4 4 divided by 2 is 2 now heres something interesting you can see that these 4 is not repeated over here generally you will find class like this 0 to 4 4 to 8 it means this is repeated upper limit is the lower limit of next class this is upper limit upper limit is lower limit of next class but here its not like that it means in these kind of classes in these kind of classes class length is class land upper limit minus lower limit that is 0 plus 1 so here plus 1 is important and you need to do plus 1 while finding class length if
upper limit is not repeated in the next class upper limit is not repeated so here you can say class and this file so here I will keep adding file so this is 7 this is 12 this is 19 this is 17 this is 22 this is 27 32 37 42 so here if you make mistake over here then all calculations will be wrong after this now I will solve these by my favorite method that is tab deviation so this will be UI and this will be fi UI and whenever you solve the question make sure that your upper limit repeats if a Perl limit does not repeat in the next class then do not forget to add one that I just explained while finding the class length you need to add one do not that here I can take anything as a that you know but when you solve the question of two missing frequencies you can take a either in front of missing frequency one or in front of missing frequency to purpose of doing this is it will eliminate one of this frequency it means it will be
zero isnt it exactly in front of a will right 0 so it will eliminate one frequency how does it eliminate that you will understand soon but as of now you can keep it in your mind that you need to take a either in front of missing frequency 1 or missing frequency 2 so here lets say this is my a exactly in front of a that will be 0 if I go up keep decreasing 1 if I go down keeping dissing 1 so this is like this keep increasing 1 keep decreasing 1 now fi UI so this will be like this so this is multiplication of these and these and here you can see f1 is eliminated it means if you find Sigma fi UI that will be 74 plus 3 F 2 3 into F ps3 f2 f1 is eliminated if you add all the frequencies what you can do add all the numbers and write f1 plus f2 with that like this some of these walls 87 87 plus f1 plus f2 now let us use the formula of step deviation because we have made table according to the
stab deviation so here this is my formula X bar must be there in the question so you can see X bar is there X bar that means mean 22 point well and sum of all the observations it means sum of these column frequency column is 125 that is again given the question so here let us substitute D value this is 22 point well a is 17 fi UI is 74 plus 3 F 2 upon Sigma fi this is the biggest mistake that students make in this here for Sigma F I never write the never write this always write what is given in the instruction sum of all the observations will be there in the instruction if it is about two missing frequencies and that is 125 so here it is 125 and class length is 5 now we can further simplify this if I take this 17 over here so 22 point 12-17 that is 5 point well is equals to 5 times 25 1 25 so this is 25 so here I have 74 plus 3 F 2 upon 25 now I will take this 25 over here so
25 into 5 point well that is 128 is equals to 74 plus 3 F 2 now I will take this 74 this side 128 minus 74 is 54 is equals to 3 F 2 now 54 divided by 3 is 18 it means 18 is equals to F 2 once you find F 2 now this information will help you how just write this information that is 87 plus F 1 plus F 2 and we know some of these 3 is 125 that is given in the instruction now I will substitute the value of F 2 so this is F 1 F 2 is 18 is equal to 125 if I add this 2 1 0 5 these and this plus F 1 is equals to 125 I will take 1 0 file that side so f 1 is equals to 20 so my missing frequencies are 20 and 18 so here this is the end of lecture I hope you find my lectures useful if you like my lecture press the like button in the next lecture I will explain how to find mode for the group the data thanks for watching
Two missing frequncies when mean is given English Explanation, Mean missing frequncy by step deviation method, Missing frequncy
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