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number one a we need to differentiate this function natural log of natural log of X so the outside function is natural log and inside function is natural log of X so we need to use chain rule its like natural log off inside function lets say natural log of inside function U and when we find
the derivative with respect to X we need to find the derivative of outside function outer function derivative of natural log is 1 over Y X natural log of U so 1 over u times derivative of inner function u prime okay so were gonna were going to use this formula to find the derivative here so
the derivative will be 1 over this inside part natural log of e^x times derivative of natural log of X derivative of inside function which is 1 over X this is that the best you can do multiply the tops 1 over the x times natural log of X u right X natural log of X final
calc I, ccu, raj dahal
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